Zerrenda:Integralak: berrikuspenen arteko aldeak

:<math>\int_{-\infty}^{\infty}{(1 + x^2/\nu)^{-(\nu + 1)/2}dx} = \frac { \sqrt{\nu \pi} \ \Gamma(\nu/2)} {\Gamma((\nu + 1)/2))}\,</math>, <math>\nu > 0\,</math>, integral hau [[Student-en t banaketa]]ren [[probabilitatearen dentsitate-funtzio]]ari lotua dago)

 

 

:<math>\int_a^b{f(x)\,dx} = (b - a) \sum\limits_{n = 1}^\infty {\sum\limits_{m = 1}^{2^n - 1} {\left( { - 1} \right)^{m + 1} } } 2^{ - n} f(a + m\left( {b - a} \right)2^{-n} )</math>